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Find the equivalent exponential expression. 12^-28 A.(12^-7)^4 B.(12^-7)^21 C.(12^-7)^-21 D.(12)^-29
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\(\Large\color{black}{ \bf a^{-b}=\frac{1}{a^{b}} }\)
Care to explain how to use that formula?
Actually you need to use the fact that\[(x ^{a})^{b}=x ^{ab}\]so the first choice is your answer because \[(12^{-7})^{4}=12^{(-7)(4)}=12^{-28}\]
\(\Large\color{black}{ \bf 12^{-28}=\frac{1}{12^{28}} =? }\)
Thank you IMStuck for very much so clarifying and using the right formula! :)
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Although SolomonZelman is correct in the general sense, I do not believe that they are asking you to rid yourself of the negative exponent in this case.
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