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1. Provide a counterexample that shows the statement is false. Explain why the counterexample makes the statement false.

If two fractions have unlike denominators, then the LCD is the product of their denominators.
Answer:

Question

(medal given out to best answer)
Show all your work.
(5 points)
Score

1.	Provide a counterexample that shows the statement is false. Explain why the counterexample makes the statement false. 

If two fractions have unlike denominators, then the LCD is the product of their denominators.
Answer:

mathstudent55 · Answer

Ok, here's an example.

$\dfrac{3}{4}$ and $\dfrac{5}{6} $

As you can see both fractions are in simplest terms (reduced) and have different denominators, 4 and 6.

The product of the denominators is $4 \times 6 = 24$, but that is not the LCD.
The LCD is 12. 12 is the smallest number that is a multiple of both 4 and 6.

anonymous · Answer

3/4 and 5/6As you can see both fractions are in simplest terms (reduced) and have different denominators, 4 and 6. The product of the denominators is 4×6=24, but that is not the LCD. The LCD is 12. 12 is the smallest number that is a multiple of both 4 and 6.