Question

14.) An isosceles triangle has an area of 48 ft2. If the base is 12 ft, what is the length of each leg?

Answer 1

I know the height is 8, but that wouldnt be the side too right?

Answer 2

\(\LARGE\color{blue}{ \rm 24=\frac{h \times 6}{2} }\)

\(\LARGE\color{blue}{ \rm 48=h \times 6 }\)

\(\LARGE\color{blue}{ \rm 8=h }\)

Answer 3

Use the Pythagorean to find the missing legs.

Answer 4

\[6^2+8^2=c^2~~~~~~~~~~~-->~~~~~~~~c=\sqrt{6^2+8^2}\]

Answer 5

the little rest is on you.

Answer 6

Thank you!

Answer 7

Anytime !