Sixth Question Of The Day (S.Q.O.T.D.)
Did I miss the fifth one?
Yes.
Been looking for it!
On this one: http://easycalculation.com/area/learn-hexa-pyramid.php Volume of a pyramid is 1/3 base X height, and so we need the base of this one.
See now, I'm having to look things up because I don't remember all of the formulas either. :D
I think wolfram alpha is reliable: http://mathworld.wolfram.com/HexagonalPyramid.html So here they are saying that the volume of a hexagonal right pyramid is 1/2 times sqrt 3 times height times apothem.
Just a moment, please. I am going to make sure I've got this one figured first!
So ... area of a hexagon is what we need. And we have a regular hexagon with a side of 4.
|dw:1401747509313:dw|
So the base is 24 sqrt 3 in area
and we need to multiply that times 1/3 and times the height which is 4 sqrt 3 So, 1/3 times 24 sqrt 3 times 4 sqrt 3
96 sqrt3 cm^3
So 8 sqrt 3 times 4 sqrt 3 = 32 times 3 = 96
Or just 96 cm^3?
I think it is just 96 cm^3, because
Yes, just 96, because 1/3 times 24 sqrt 3 gives you 8 sqrt 3 and then 8sqrt3 times 4 sqrt 3 gives
32 times the sqrt 3 squared
Okay.
which would be 36 X 3 or 96
Okay, I tagged you on another question.
Problem is, I remember the really simple formulas and then derive the other stuff! Sorry that took so long. :)
That's fine, I was enjoying my food.
While I was looking at your comments.
Join our real-time social learning platform and learn together with your friends!