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Mathematics 8 Online
OpenStudy (anonymous):

Help! Graph question

OpenStudy (anonymous):

OpenStudy (anonymous):

it's A right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

plz explain why?

OpenStudy (anonymous):

For x intercept you need to find the distance from y axis

OpenStudy (anonymous):

see which line is -6 away from origin or from origin count towards -6 along the x axis

OpenStudy (anonymous):

I'm confused..I have to be honest

OpenStudy (anonymous):

@aajugdar

OpenStudy (anonymous):

An easy way to find intercepts is to reduce any equation in the for x/a + y/b =1 for instance to 2x + 3y =12 In this case reduce the qquation to 2x/12+ 3y/12 = 1 (dividing by 12 on both sides then it becomes x/6 + y/4 = 1 and intercepts are x=6 and y =4 now if suppose x= -6 then it is x/(-6) = 1 no y term so find a line which intersects x axis at -6

OpenStudy (anonymous):

-6 is a number btw -10 and -5 also x=-6 means find -6 on x_axes then draw a parallel to y

OpenStudy (anonymous):

|dw:1401784013674:dw|

OpenStudy (anonymous):

no xD

OpenStudy (anonymous):

its DDDDDDDDDDDDDDDDDD

OpenStudy (anonymous):

see if it make sense to u

OpenStudy (anonymous):

crap!

OpenStudy (anonymous):

oyeee

OpenStudy (anonymous):

ikr right , but this crap will make u have F , if u dint focus enough :P

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