Help me if you can I'm feeling down... Help me get my feet back on the ground!!
Got to fill in all those blanks!
A rectangular storage container with an open top has a volume of 16 m3. The length of its base is twice its width. Material for the base costs $6 per square meter; material for the sides costs $2 per square meter. Express the cost of materials as a function of the width of the base.
looks like the actual information to fill in is missing from the picture ....
Actually, it should all come from here: A rectangular storage container with an open top has a volume of 16 m3. The length of its base is twice its width. Material for the base costs $6 per square meter; material for the sides costs $2 per square meter. Express the cost of materials as a function of the width of the base.
@amistre64
Wow!!! Have you learned any of this stuff?
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V = lwh h = V/lw, but l = 2w h = V/2w^2 Ab = l*w As = lh+lh+wh+wh
well, filling in boxes, if we have an area of lw, and it costs k per ... then the first box has to be what?
The first box, answer is 6.
good, and they basically give you the next 2 boxes for you
Please excuse me, I am delirious from working this all day. Can you show me those 2? lol sorry.
2(area of one side) + 2(area of the different side) and there are 2 sides each 2[ 2(area of one side) + 2(area of the different side)]
how do they define the needed areas?
you mean by h, 2w, w?
yeah
2(wh) + 2(2wh) gives us 4 sides .... at $2 each is therefore 2[2(wh) + 2(2wh)] what do we put in the boxes?
really? 2[2(wh) + 2(2wh)] 2[2(....) + 2(2(.....))] what goes in the boxes?
Duh me.
Yes yes. Sorry about that.
now the sum of the total cost is the addition of everything we have filled in so far .... so the next 3 boxes are the exact same thing as the first 3 boxes we just did ...
ok. Thanks.
6(2w^2) + 2[2wh + 2(2wh)] simplify it into : ___w^2 + ___wh
now they say to eliminate h, use the fact that the volume is equal to 16 m^3, then they ask you to fill in the box that says the volume is equal to _____
then they say ... divide off the 2w^2, and simplify the results for h
*we are right with everything up to this point* THANK YOU! 16
then it says to take that h, in terms of w, and fill it into the equation that we got to begin with ...
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have you finished yet? when you do post your stuff and ill post mine
Sorry. This [site] is so slow.
bunch more 12's an 8 or 2, and other stuff. Got it. Thanks.
:) it was basically alot of filling in what they gave you already :)
U got the deepfreeze in your windows? Thanks again!
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