Question

Please Help

Answer 1

Would you like help with your question?

Answer 2

So you are given \(\sqrt{6}(6 + \sqrt{3})\) and are expected to simplify it, correct?

Answer 3

That is not exactly the complete simplification

Answer 4

The truth is is is not necessary to distribute \(\sqrt{2}\)

Answer 5

Do you agree that \(\sqrt{6}(6 + \sqrt{3}) = \sqrt{2 \dot\ 3}(6 + \sqrt{3})\)

Answer 6

And that
\(\sqrt{2 \dot\ 3}(6 + \sqrt{3}) = \sqrt{2}\sqrt{3}(6 + \sqrt{3})\)

Answer 7

Yes.

Answer 8

At this point, it is useful to distribute the\(\sqrt{3}\)

Answer 9

What do you get after distributing \(\sqrt{3}\)?

Answer 10

√6(6 + √3) ?

Answer 11

Do you know what it means to distribute \(\sqrt{3}\)?

Answer 12

If you have \(a(b + c)\) and you distribute the a, you end up with \(ab + ac\)

Answer 13

Are you still there @Hero ?

Answer 14

Yes, I'm waiting for you to distribute \(\sqrt{3}\)

Answer 15

Wouldn't it just be √2(6 + √6)

Answer 16

Not exactly.

If you distribute \(\sqrt{3}\) you should have gotten \(\sqrt{2}(6\sqrt{3} + \sqrt{3}\sqrt{3})\).

I'm surprised. Do you know how to distribute the 6 in

\(6(2x + 3)\)?

Answer 17

nervermind i got the answer. thanks for helping

Answer 18

What do you believe is the correct answer and how did you get it?