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What are the sine, cosine, and tangent of 5 pi over 4 radians?
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please help
sin(5pi/4) = sin(pi + pi/4) = -sin(pi/4) = \(\large -\dfrac{\sqrt{2}}{2}\)
tangent?
cosine?
work cosine same way
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cos(5pi/4) = cos(pi + pi/4) = -cos(pi/4) = \(\large -\dfrac{\sqrt{2}}{2}\)
can you walk me through it please
so sin and cos have same values for 5pi/4 ^
For tan, simply take the ratio of sin and cos - you would get : tan(5pi/4) = \(\large 1\)
sin Θ = negative square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1
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right?
looks good
thanks
yw
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