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Mathematics 16 Online
OpenStudy (anonymous):

Solve for c in terms of a and b: bc+ac=ab Thanks :)

OpenStudy (epoweritheta):

bc+ac=ab bc-ab=ac b(c-a)=ac b=ac/(c-a)

OpenStudy (owlcoffee):

Whenever we have only letters and are not specified any special properties they posses, then they are variables that count as "any number". So just treat them as if they were any number, leave it solved for that since you are not specified with any peoperty or condition they posses. So if you have: \[bc+ac=ab\] You take common factor "c": \[c(b+a)=ab\] and dicide both sides by (b+a): \[c=\frac{ ab }{ (b+a) }\] and that is what we call "solving for variable".

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