Ask
your own question, for FREE!
Mathematics
7 Online
Solve for c in terms of a and b: bc+ac=ab Thanks :)
Still Need Help?
Join the QuestionCove community and study together with friends!
bc+ac=ab bc-ab=ac b(c-a)=ac b=ac/(c-a)
Whenever we have only letters and are not specified any special properties they posses, then they are variables that count as "any number". So just treat them as if they were any number, leave it solved for that since you are not specified with any peoperty or condition they posses. So if you have: \[bc+ac=ab\] You take common factor "c": \[c(b+a)=ab\] and dicide both sides by (b+a): \[c=\frac{ ab }{ (b+a) }\] and that is what we call "solving for variable".
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
serenitystXrgazer:
Getting sent to anti gay christian covestion camp in a few weeks, any tips. guys i think im cooked.
Aubree:
Guys, what does love feel like? I've been getting a tight chest and when I talk to him my heart rate hangs out around 100-120 beats per min, and when he doe
thereneelg:
ok... anyone have advice?? ...I did Choir all throughout Middle school and have ALWAYS been put in Soprano those three years.
kamariana:
The Byzantine Procopius is known for (5 points) reconquering much of the old Roma
chuckD:
hellp!!! what does it mean to describe a scientist as skeptical Why is sceptical
DoltonCarlee:
So like do y'all know anything about the first world war?
thehearken:
anyone know how to explain this so its easier for me to understand? b(1)=2, b(n)=
8 hours ago
1 Reply
0 Medals
15 hours ago
10 Replies
2 Medals
2 days ago
6 Replies
1 Medal
3 days ago
0 Replies
0 Medals
3 days ago
2 Replies
1 Medal
2 days ago
2 Replies
0 Medals
2 days ago
5 Replies
2 Medals