Question

Eliminate the parameter.

x = t - 3, y = t2 + 5

a. y = x2 + 6x + 14

b. y = x2 - 14

c. y = x2 - 6x - 14

d. y = x2 + 14

Answer 1

I don't really understand the question.. It's all you loser66

Answer 2

t=x-3??

Answer 3

oh no

Answer 4

\[x=t-3\] solve for \(t\)

Answer 5

@thinktallthoughts
you have t = x +3 not x -3, right?

Answer 6

oh yeah.

Answer 7

so then it's y=(x+3)2+5??

Answer 8

now, just replace that t on y = t^2 +5
DAT SIT

Answer 9

Yup

Answer 10

thx!

Answer 11

:)