Question

For a medal if you help: Given the reciprocal squared function that is shifted right 3 units and down 4 units. Write this as a rational function and find the horizontal and vertical intercepts and the horizontal and vertical asymptotes.

Answer 1

@dan815 @ganeshie8 @SithsAndGiggles

Answer 2

I figured out that the rational function looks like 1/(x-3)^2 - 4

Answer 3

oh goood

Answer 4

or with a common denominator, 1-4(x^2-6x+9)/(x-3)(x-3)

Answer 5

How do you find the horizontal and vertical intercepts and asymptotes?

Answer 6

@campbell_st

Answer 7

@iambatman

Answer 8

https://www.morainevalley.edu/AcademicSkills/Folders%20for%20Web%20Access/ASC%20Math/MATH%20141/MAT%20141%20Chapter%204.2%20More%20On%20Graphs%20Of%20Rational%20Functions.pdf

Answer 9

OK, so I found the vertical asymptote at f(x) = -4 and the horizontal asymptotes at (2.5, 0) and (3.5, 0) but looking at the answer it then says to evaluate at 0 and the vertical intercept is at (0, -35/9) <-- not sure how to get the vertical intercept

Answer 10

@aajugdar

Answer 11

you put y= 0 and find for x

Answer 12

so in 1-4(x^2-6x+9)/(x-3)(x-3) I set all of it to 0?

Answer 13

yes
so put denominator to other side and it becomes 0
solve 1-4(x^2-6x+9) = 0