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Mathematics 41 Online
OpenStudy (anonymous):

A sandbag was thrown downward from a building. The function f(t) = -16t2 - 64t + 80 shows the height f(t), in feet, of the sandbag after t seconds: Part A: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function. (4 points) Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? (4 points)

OpenStudy (anonymous):

Part C: Use your answer in part B to determine the axis of symmetry for f(x)? (2 points)

OpenStudy (john_es):

Well, the first part tells you to factor the polinomy, \[-16t^2-64t+80 \] You can do it because \[-16t^2-64t+80=0 \Rightarrow-t^2-4t+5=0\] has solutions, \[t=\frac{4\pm\sqrt{{4^2+4\cdot80}}}{-2}\] You will obtain two solutions, the x-intercepts.

OpenStudy (john_es):

As t means time only the positive solution has physical sense.

OpenStudy (anonymous):

So the factored function is -16^2-64t+80, then what about the meaning of the x-intercept. It means time only the positive solution has a physical sense?

OpenStudy (john_es):

The correct one it is, \[t=\frac{4\pm\sqrt{4^2+4\cdot5}}{-2}\] The two solutions are t=-5 and t=1. The factored polinomy is, f(t)=-16(t+5)(t-1)

OpenStudy (john_es):

To interpret the meaning of the x intercept you should know that only positive time has physical sense. So the positive time indicates you the time when the sandbag hits the ground.

OpenStudy (anonymous):

Oh! Got it, so my answer "The factored function of -16^2-64t+80 is f(t)=-16(t+5)(t-1). The x-intercepts are when the sandbag hits the ground."

OpenStudy (john_es):

Exactly. But I would add "the positive x-intercept"

OpenStudy (anonymous):

Okay thanks, can we work on part B?

OpenStudy (john_es):

To complete the square, you should put it in the form \[(a+b)^2=a^2+b^2+2ab\]

OpenStudy (john_es):

It should be something like this, \[f(t)=-16(t^2+4t-5)=-16(t^2+4t+4-4-5)=\\=-16((t+2)^2-9)=-16(t+2)^2+144\]

OpenStudy (john_es):

You will find the vertex then in the point (-2,144).

OpenStudy (anonymous):

Okay, so then to find the vertex I have to put a number in for all the "x's" but what number? Wait, (-2,144) is the vertex?

OpenStudy (john_es):

Yes, the vertex has x coordinate -2, and y coordinate 144. It is a maximum.

OpenStudy (anonymous):

Okay so "The completed square of the function is -16(t+2)^2+144, and the vertex is (-2, 144). This would be a maximum."

OpenStudy (john_es):

Yes.

OpenStudy (anonymous):

Yay! Then part c ask to find the axis of symmetry.. The formula is x=-b over 2a I think.

OpenStudy (john_es):

You don't need the formula now, but you can use it. You don't need the formula because you have found the axis in the part B. x=-2.

OpenStudy (anonymous):

So the axis of symmetry is just x=-2?

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