Solve 3x2 = -12x - 15. Please helppppppppp!
A.) x = -4 ± 2i B.) x = -4 ± i C.) x = -2 ± 2i D.) x = -2 ± i
\[3x^2 = -12x-15\]Put it in the form\[ax^2+bx+c=0\]
Solve for x using the quadratic formula\[x=\frac{b\pm\sqrt{b^2-4ac}}{2a}\]
When plugging in the first part would i chnge the sign of -12 or?
For example would it be 3x2+12+15=0?
Change the sign... I guess you could think of it like that. What I would do is add 12x to both sides of the equation, to keep it equal.\[3x^2\color{red}{+12x}= -12x\color{red}{+12x}-15\]\[3x^2+12x= 15\]then add 15 to both sides\[3x^2+12x\color{red}{+15}= -15\color{red}{+15}\]\[3x^2+12x+15=0\]
sorry, in that first step i meant =-15
So would i use the quadratic formula now?
yes
so it would be |dw:1401992319555:dw|
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