Question

Help!

Answer 1

question plz

Answer 2

^

Answer 3

Im getting to that part.... one sec

Answer 4

ok here it is @Hotchellerae21 @Somy @me_Purpleswag

Answer 5

number 12

Answer 6

did u do any working urself?

Answer 7

yes here I'll show u @Somy

Answer 8

\[8^2 + (x-6)^2 = c^2\]
\[x^2 - 12x + 100\]

Answer 9

I foiled out the (x-6) ^2

Answer 10

okay do u already know the answer?

Answer 11

no i have no clue

Answer 12

ok i did it in a different way and my x= 16.6

Answer 13

how did u get it?

Answer 14

how about i write the whole working on the paper and take a pic and then show u, if u don't get what i did i'll clear ur doubt ok?

Answer 15

sounds great! thx

Answer 16

ok then gimme some time :) @B_O_R_E_D

Answer 17

np! @Somy

Answer 18

in the big triangle base ^2 =x^2 -10^2
base ^2 =x^2 -100


in small triangle base ^2 =(x-6)^2 +8^2

so x^2 -100=(x-6)^2 +8^2

x^2 -100=x^2-12x+36+64

x^2 -x^2 +12x =100+100
so 12 x=200
x=200/12

Answer 19

I'm sorry i'm trying to understand what you just did :/

Answer 20

ok done

Answer 21

lol ok :) @Somy

Answer 22

look at the working no 1 first

Answer 23

working no 2

Answer 24

working no 3

Answer 25

i hope u understand my writing though lol @B_O_R_E_D

Answer 26

just finished #1.....

Answer 27

okay then look at the working and tell me if u don't understand something, ok?

Answer 28

ok finished #2...so far so good :)

Answer 29

ok so x is 16.6?

Answer 30

yup that's what im getting :D

Answer 31

THANK YOU!!!!!!!!!!! @somy

Answer 32

I'm going to copy this as an example for my other problems :)

Answer 33

you are welcome :D @B_O_R_E_D

Answer 34

hehe its pure trigonometry and i love trigonometry that's why i could help :)

Answer 35

well I'm glad! how r u with vecotrs ?! lol

Answer 36

good job @Hanishala though ur way is a bit different but we got same answers :D

Answer 37

owh my that will depend on question @B_O_R_E_D

Answer 38

ok I'll post it :)

Answer 39

np :D

Answer 40

thanks @Somy

Answer 41

you are welcome :) @Hanishala