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@aajugdar Solve (z + 6)^2 = 5.
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@aajugdar
hmm so you can write (z+6)^2=5 as \[z^2+12z+36=5 \]
now \[z^2+12z+31=0 \]
this one cant be factorised so we use the formula \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2 }\]
2a* in denominator
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Im 100% confused
^ there you go
This would be the answer.
no there is minus sign b4 6
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\[x=-6\pm \sqrt{5}\]
Yeah sorry I sent the wrong thing. Thank you. You're really smart.
haha,i dnt deserve that compliment :P
You're the reason I passed the test. So yah you do LOL
LOL
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