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MIT 18.06 Linear Algebra, Spring 2010 20 Online
OpenStudy (epoweritheta):

Is there any proof or theorem that says "The eigenvector space of a matrix A is <= n " for a n x n matrix A ??

OpenStudy (anonymous):

indirectly spokens yes. A nxn matrix can only have n or less non-similar eigenvalues. Each eigenvalue has one "partner" eigenvector. So there can only be n or less independent eigenvectors. (Think about diagonalisation) Note: If you hear somebody say "THE eingenvector to this eigenvalue", they mean one REPRESENTATIVE of all linear combinations of this eigenvector.

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