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Mathematics 15 Online
OpenStudy (anonymous):

Help me? y = 3x^2 + 2. a. What is the domain? b. What is the range?

OpenStudy (anonymous):

the domain is all real numbers

OpenStudy (eyust707):

domain and range corresponds to x and y

OpenStudy (eyust707):

what x values are you allowed to put in there?

OpenStudy (eyust707):

what y values will those x values produce?

OpenStudy (eyust707):

so yea in this case we can plug in any real number we want... that means the domain is all real umbers

OpenStudy (eyust707):

but what about the range?

OpenStudy (eyust707):

The graph is an easy way to tell the range|dw:1402005917931:dw|

OpenStudy (eyust707):

the y values of the graph will go up and up forever

OpenStudy (eyust707):

but it will never be lower than what value?

OpenStudy (anonymous):

From the graph you can tell that the range will be everything above two because the range refers to the y values... so [2, infinity)

OpenStudy (anonymous):

So, the range is 2 and the domain is infinity ?

OpenStudy (eyust707):

nope close you still have domain and range a little bit confused

OpenStudy (eyust707):

the range is "all numbers"

OpenStudy (eyust707):

we are allowed to plug in any number we want and the equation will be valid

OpenStudy (eyust707):

the domain is the answer to this question: "what values for y is it possible for that function to be?"

OpenStudy (eyust707):

well that function could be any number greater than 2

OpenStudy (eyust707):

*greater than or equal to so the range is all number greater than or equal to 2

OpenStudy (anonymous):

|dw:1402006394714:dw|

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