Question

Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y=7/5x-3/5.
A. 5x + 7y = 1
B. 7x + 5y = –13
C. 7x + 5y = –1
D. 3x + 5y = 7

Answer 1

you know the form of equation y = mx + c where m is the slope of line and c is some constant?

Answer 2

yeah

Answer 3

here the slope of given line is y = mx+c , we need m value so,
m =7/5
and slopes of perpendicular lines have a property if m1 and m2 are slopes of perpendicular lines then
product of slopes = -1
so m*7/5 = -1 => m = -5/7 { this is what the slope of our required line

Answer 4

now you have a point (–4, 3) and slope -5/7, use point-slope formula :)

Answer 5

ohh ok I get it

Answer 6

:)