Question

Help with math problem. Completely stumped

Answer 1

Simplify\[\frac{ 7 }{ 7x+x^2 }\]

Answer 2

I think I may be able to see. Hold on tho

Answer 3

If you need possible answers I can give them

Answer 4

Yeah!

Answer 5

A.\[\frac{ 1 }{ 7+x }\]; Where x isn't 7
B.\[\frac{ 1 }{ 7x } ; Where x \neq 0\]
C.\[\frac{ 1 }{ 7+x } : where x \neq 0,7\]
D. 1/7

Answer 6

This algebra 2?

Answer 7

I believe it's algebra 1 b

Answer 8

The answers I have don't match any that yo have:/ So I know I'm wrong. :/

Answer 9

@dan815

Answer 10

He may be able to help, he's helped me a lot.

Answer 11

Well I have absolutely no clue, so if you're close to any of them, I'll probably just choose that one

Answer 12

It's almost as if they're taking the reciprocal...

Answer 13

can you check the question and see if there is an x in the numerator...?

Answer 14

yeah because I kept getting that the numerator was part of the answer

Answer 15

!!!! That 7, is supposed to be an x, I have no clue how I messed that up... Sorry

Answer 16

ok... so you'll be able to simplify it now

\[\frac{x}{x(7 + x)}\]

Answer 17

\[\frac{ x }{ 7x+x^2 }\]

Answer 18

cancel the common factor... then look a the restriction in the denominator

what value can't x have...?

Answer 19

and I think one of your restrictions should be x can't be -7

Answer 20

No, it either can't be -7, or 0 depending on the answer

Answer 21

Woops, thought that said positive 7, I shouldn't be doing math at 4:15 am :/

Answer 22

Know that feel^

Answer 23

But there's still 22 questions and I don't want to do work tomorrow

Answer 24

): I have a lot too .-.

Answer 25

Sorry, I can't be much help, good luck though.