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which part of the qu solved through factorizingadratic formula tells whether it can be
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You can factor the \(\large\color{blue}{ \rm ax^2+bx+c }\) if \(\large\color{blue}{ \rm b^2-4(a)(c)}\) (the discriminant) is a perfect square.
thnx
plz solve for x in 16x squared -81=0
\(\large\color{blue}{ \rm 16x^2-81=0 }\) \(\large\color{blue}{ \rm 16x^2=81 }\) \(\large\color{blue}{ \rm 16x^2=9^2 }\) \(\large\color{blue}{ \rm 4^2x^2=9^2 }\) \(\large\color{blue}{ \rm (4x)^2=9^2 }\) \(\large\color{blue}{ \rm 4x=± 9 }\) \(\large\color{blue}{ \rm x=± 9/4 }\)
i think you are a genius...thnx
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4x squared + 3 = 12x
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