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Mathematics 14 Online
OpenStudy (anonymous):

fuggin hate math

OpenStudy (anonymous):

Okay

OpenStudy (solomonzelman):

\(\large\color{blue}{ \rm -:( }\)

OpenStudy (anonymous):

me tooo!

OpenStudy (solomonzelman):

I love math (and science) :)

OpenStudy (anonymous):

Math is too hard -_-

OpenStudy (anonymous):

Because you don't understand it???

OpenStudy (anonymous):

i neeeeed help.

OpenStudy (anonymous):

Solve for the variable. Reduce the answer to lowest terms. 1/8r=24?

OpenStudy (solomonzelman):

multiply both sides times 8

OpenStudy (anonymous):

Really? My teacher's a fuggin retard! Got us doin some stupid shhhhhhhhhhhhhhhhh

OpenStudy (anonymous):

i mean what what did she say

OpenStudy (anonymous):

She's got us rearranging the whole equation and multiplying both sides then dividing by other stuff.

OpenStudy (anonymous):

That is right @Kracker @katiebum479 post it there <--------

OpenStudy (anonymous):

@No.name Select the equation that corresponds with the given graph. a. y = -5x + 5 b. y equals negative 1 over 5 times x + 5 c. y equals 1 over 5 times x + 5 d. y = 5x + 5

OpenStudy (anonymous):

What is the general/standard form of a linear equation?

OpenStudy (anonymous):

@SolomonZelman u may like to join

OpenStudy (solomonzelman):

\(\large\color{blue}{ \rm (0,5)~~ (-1,0) }\) are the 2 points of the line.

OpenStudy (anonymous):

honestly no idea

OpenStudy (solomonzelman):

Hence you can exclude C and D, because the slope of the graph is negative And exclude B because the slope is fore sure more than │1│ .

OpenStudy (anonymous):

This stiff is so confusing, but thank you @SolomonZelman

OpenStudy (anonymous):

No point in solomon explaining if didn't get anything

OpenStudy (anonymous):

you*

OpenStudy (anonymous):

I have an IEP in algebra, and i dont get the help i need for math and so i have to take online classes and its just as hard for me... i do pay attention just have a really hard time

OpenStudy (anonymous):

join a tutor probably , just a suggestion

OpenStudy (anonymous):

well thank you @No.name

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