Question

Sketch curve with equation y= 2x-1/x+1
@ganeshie8 @zpupster
CAN ANYONE HELP ME

Answer 1

vertical asymtote= -1

Answer 2

What's ur method ( @ganeshie8 ) to get the horizontal asymtote

Answer 3

long division method?

Answer 4

@ganeshie8

Answer 5

@SolomonZelman

Answer 6

take the ratio of leading coefficients of numerator and denominator

Answer 7

\(\large y= \dfrac{2x-1}{x+1}\)

leading coefficient of numerator = 2
leading coefficient of denominator = 1

So horizontal asymptote is :
\(\large y = \dfrac{2}{1} = 2\)

Answer 8

\(\LARGE\color{blue}{ \rm y=\frac{2x-1}{x+1}}\)


\(\large\color{blue}{ \rm x=-4,~~~-->~~~y=3,~~~->~~~(-4,3)}\)
\(\large\color{blue}{ \rm x=-2,~~~-->~~~y=5,~~~->~~~(-2,5)}\)
\(\large\color{blue}{ \rm x=0,~~~-->~~~~y=-1,~~~->~~~(0,-1)}\)
\(\large\color{blue}{ \rm x=2,~~~~-->~~~y=1,~~~->~~~(2,1)}\)

graph a couple points, and draw the curve

Answer 9

Thanks Ganesh & Solomon

Answer 10

You can do that for any rational function that has same degree for both numerator and denominator

Answer 11

http://www.coolmath.com/precalculus-review-calculus-intro/precalculus-algebra/18-rational-functions-finding-horizontal-slant-asymptotes-01.htm

Answer 12

:D