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Mathematics 21 Online
OpenStudy (anonymous):

r

OpenStudy (anonymous):

use the midpoint formula?

hero (hero):

You may use the midpoint formula to find point X

hero (hero):

However if you're trying to do this without graph paper, I wouldn't suggest doing so.

OpenStudy (anonymous):

@hero for the midpoint I got (3,4)

hero (hero):

Okay, great

hero (hero):

1. Plot the given points on xy plane 2. Find the mid point of PQ 3. Label the mid point as point X 4. Rotate segment PX 90 degrees counterclockwise using point X as the pivot. 5. Label the endpoint of the rotated segment as P'X 6. Rotate segment QX 90 degrees counterclockwise using X as the pivot. 7. Label the endpoint of the rotated segment as Q'X 8. Either P' or Q' will be the point of interest.

OpenStudy (anonymous):

The rest I'm completed confused about.. :/

OpenStudy (anonymous):

completely*

hero (hero):

Basically segments PX and P'X form a right angle with point X as the vertex

hero (hero):

P' is one of the points you are looking for

hero (hero):

PX and P'X have slopes that are negative reciprocals of each other.

OpenStudy (anonymous):

I with you so far :)

hero (hero):

What is the slope of PX?

OpenStudy (anonymous):

-3/2

hero (hero):

So what is the slope of P'X?

OpenStudy (anonymous):

That's where I'm confused, is it the reciprocal 2/3?

hero (hero):

Yes

hero (hero):

Now, that you know this, I'll have to walk you through how to get from point P to P'

hero (hero):

Start with point P then count two units to the right. Then count 3 units down. You should be at point X afterwards. From there, count two units down, then 3 units to the left. That will be point P'

hero (hero):

Let me know the coordinates of P'

OpenStudy (anonymous):

P (1,7) and Q (5, 1)

hero (hero):

Those are the given coordinates.

hero (hero):

P' is the point after rotation

hero (hero):

Follow the steps I gave you previously to find P'

OpenStudy (anonymous):

See I don't understand how to do all that...

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