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Mathematics 8 Online
OpenStudy (anonymous):

An inchworm ran into a log while on his way to the raspberry patch. The diameter of the log is 32 cm. How far did the inchworm travel while on the log? Round your answer to the nearest centimeter.

OpenStudy (anonymous):

OpenStudy (perl):

the inchworm traveled half a circle circumference. C = 2*Pi*radius we want half of C

OpenStudy (perl):

the inchworm traveled half a circle's circumference. C = 2*Pi*radius And we we want half of C so 1/2 C = Pi * radius. and radius is half the diameter so the distance is Pi * 16

OpenStudy (anonymous):

3.14*16=50.25

OpenStudy (perl):

if your teacher wants you to approximate Pi with 3.14 , then yes

OpenStudy (anonymous):

my choices are A.\[2\sqrt{15}\pi cm\] B.\[4\sqrt{15}\pi cm\] C.\[30picm\] D.\[900picm\]

OpenStudy (anonymous):

@perl

OpenStudy (perl):

im not sure why you have those answer choices, they dont match the question

OpenStudy (mathmate):

The closest one is 4sqrt(15). Do not forget that it is an inch work, meaning that it is 2.54 cm long. So the actual distance "while on the log" starts counting when it is completely on the log. So the distance travelled is 16pi - 2.54 cm = 47.7 cm, while 4sqrt(15)pi is 48.67 cm, within 1 cm.

OpenStudy (perl):

typo there, *inchworm*

OpenStudy (mathmate):

Thank you @perl

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