Question

Helpppp plzzzzz
Part 1: Simplify f(x) = the quantity 2 x-squared plus 3x plus 1 all over 2x plus 1. (4 points)

Part 2: Using complete sentences, explain why f(1) = 2, f(0) = 1, and f(-1) = 0, yet f(-one¨Chalf) is undefined. Be sure to show your work. (4 points)

Answer 1

well you need to factor the quadratic in the numerator... there is a common factor

\[\frac{2x^2 + 3x + 1}{2x + 1}\]

Answer 2

Ah ok not sure how to do that but ok lol thanks

Answer 3

well the numerator becomes

\[\frac{(2x + 1)(x + 1)}{(2x + 1)}\]

Answer 4

for part 2 substitute

x = 1 into the expression and get an answer

then

x = 0 get the answer

x = -1 get the answer

for

x = -1/2 show that when you substitute it into the denominator you get zero...

any fraction is undefined when a zero denominator occurs... this is the restriction...

hope it helps

Answer 5

ah cool thanks Helps a lot