Question

prove: sinθ - sinθ * cos^2 θ = sin^3 θ, show all work please!

Answer 1

@hartnn Im sorry, theres one more for my guide i missed XC

Answer 2

did u know ?
\(\Large \sin^2 \theta +\cos^2\theta =1 \)
?

Answer 3

nope, im 100% unsure of how this question works

Answer 4

so now you know :)

isolate cos^2 theta from that formula

Answer 5

sin^2θ=1?

Answer 6

wait wait

Answer 7

Nope, I'm lost ._.

Answer 8

\(1-\cos^2 \theta =1- (1-\sin^2 \theta ) = \sin^2 \theta \)

see if you get this ?

Answer 9

Ok i understand that

Answer 10

sinθ - sinθ * cos^2 θ

factor out sinθ
what do u get?

Answer 11

sin^3(θ) ?

Answer 12

left side = sinθ - sinθ * cos^2 θ = sinθ ( 1- cos^2 θ) = sin(θ) * sin^2(θ) =sin^3(θ) = right side
hence proved

Answer 13

You make this so easy ._. Before you math was just mumbo jumbo but after you explain it it seems so obvious!

Answer 14

thats a nice compliment!
you're welcome ^_^