OpenStudy (anonymous):
Find mBC if Angle A is equal to 18° and mDC measures 48°.
OpenStudy (anonymous):
OpenStudy (inkyvoyd):
lol, if you want help, let us know what you've tried and what you don't understand about the problem.
geerky42 (geerky42):
Why would you reverse google search on profile picture?
OpenStudy (anonymous):
What do you mean nice image? its from paint
OpenStudy (anonymous):
I really havent tried anything because I dont understand it.
OpenStudy (anonymous):
hahah thats exactly what I was trying to avoid, somebody google searching me
OpenStudy (anonymous):
Use this theorem to solve the problem. If a secant and a tangent intersect in the exterior of a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. So the two intercepted arcs are BC and DC. The angle formed is 18 degrees. Using that information, we get 18=1/2(48-BC). Solving for BC we get. BC = 48-36 or BC=12
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