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How do I differentiate g(f(x^2))?
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I know this has to do with the chain rule, but for some reason it is confusing me.
\((f(g(x))' = f'(g(x))\times g'(x)\) basically we derivate outer function, and multiply it with derivative of inner function
I get g'(f(x^2) X f'(x^2) X 2x.
correct!
Oh okay, I think I see. I was trying to do it a shorter way, but I gave in and used substitution, and it makes sense now. xD Thanks.
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welcome ^_^
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