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f = 5gh for h
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Hi there! :) \[\Large\rm f = 5g\color{orangered}{h}\]So we want to isolate our h. In order to do that, we need to move the junk to the other side. We have 5 and g `multiplying` our h. The inverse of multiplication is division. So we'll `divide` each side by 5 and g.
Dividing gives us:\[\Large\rm \frac{f}{5g}=\frac{5g\color{orangered}{h}}{5g}\]
On the right side, 5g and 5g divide evenly.\[\Large\rm \frac{f}{5g}=\frac{\cancel{5g}\color{orangered}{h}}{\cancel{5g}}\]
Do you see how that works? :o
Yes, thanks so much
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Cool. and, \(\Large\bf \color{#008353}{\text{Welcome to OpenStudy! :)}}\)
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