What is the opening direction of a parabola with the equation x=-y^2? PLEASE HELP
its concave left
and symmetrical about the y axis
Thank you :)
notice that if the equation was x = y^2, x will ALWAYS be positve no matter what y is. so you equation is x = -y^2 means x will always be negative. so it opens left.
can you guys solve this by graphing?? y = -x + 4 (x - 3)2 + y2 = 25
y = -x + 4 (x - 3)2 + y2 = 25
yep... you need to solve this by substitution so take the 1st equation and substitute it into the 2nd equation \[(x - 3)^2 + (4 - x)^2 = 25\] 1st simplify the equation and the solve for x when you get x, there are 2 values...I think substitute into the 1st equation to find y
it says to solve this system by graphing because I need the coordinates lol
Join our real-time social learning platform and learn together with your friends!