Mathematics
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OpenStudy (anonymous):
Find the inverse of f(x) = (5x-4)/(x+4)
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OpenStudy (anonymous):
I want to see if I'm on the right track...
y = 5x-4/x+4
(y+4)*x = 5y-4
xy + 4x - 4x = 5y - 4
xy = 5y-4-4x
jigglypuff314 (jigglypuff314):
that is correct so far
jigglypuff314 (jigglypuff314):
now get the 5y to the other side
and factor out the y
OpenStudy (anonymous):
xy-5y=-4-4x
OpenStudy (anonymous):
5(y-x)=-4-4x
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OpenStudy (anonymous):
Oh I factored out the wrong thing
OpenStudy (anonymous):
y(-5+x)=-4-4x
jigglypuff314 (jigglypuff314):
yes
then divide (-5+x)
OpenStudy (anonymous):
y = -4-4x/-5+x
jigglypuff314 (jigglypuff314):
that is correct
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OpenStudy (anonymous):
wow that is a lot of steps for this one
OpenStudy (anonymous):
could I have taken a shortcut?
jigglypuff314 (jigglypuff314):
I don't see any short cuts...
jigglypuff314 (jigglypuff314):
you could, however, factor out and cancel out some negatives
OpenStudy (anonymous):
can you give me an example?
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jigglypuff314 (jigglypuff314):
I got f^-1(x) = 4(x+1) / (5-x)
OpenStudy (anonymous):
That is a nicer solution... mine is (-4-4x)/(-5+x) and it was correct
jigglypuff314 (jigglypuff314):
yes it was
OpenStudy (anonymous):
now I wonder how you got your answer
jigglypuff314 (jigglypuff314):
........
(y+4)*x = 5y-4
xy + 4x = 5y - 4
-xy -xy
4x = 5y - xy -4
+4 +4
4x + 4 = 5y - xy
4x + 4 = y(5-x)
y = (4x+4)/(5-x)
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OpenStudy (anonymous):
Oh so you subtracted xy first and I subtracted 4x