Chelsea is trying to find the equation of a quadratic that has a focus of (1, 3) and a directrix of y = −3. Describe to Chelsea your preferred method for deriving the equation. Make sure you use Chelsea's situation as a model to help her understand.
If the directrix is at y = -3 and the focus is at (1, 3), what do you know about the vertex?
I honestly have no idea.
Oh boy. Are you familiar with what type of a quadratic this is and what it looks like?
I suck at/hate math but yes.
So what is it? The graph? What does it look like?
The parabola opens up
Very good. Now if I were you, I would take out a sheet of graph paper and plot the focus and the draw the directrix. Can you do that? It will help you tremendously!
Got it
|dw:1402280679569:dw|Is that what yours looks like? (Mine is quite skewed without the benefit of graph paper!)
Yes, just straight lol
gotcha!! Do you know where, in relation to the focus and the directrix, where the vertex lies? Do you know the line of symmetry?
axis of symmetry= 1
x = 1, right. What about the vertex? What is its coordinates?
Well the focus is (1,0) what would that make the vertex?
Actually, re-read your problem. The focus is at (1,3). The vertex is at (1, 0). Do you know why?
Well that clears my confusion up lol
Does it? Completely? Do you know how to proceed from here or do you still need some assistance?
I need assistance, What do I tell Chelsea lol
Tell Chelsea to pay attention in class; you have your own problems! LOL!!!!!!!
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