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AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to AB ? A) 5x – 3y = 0 B) -x + 3y = 0 C) -5x – 3y = 0 D) 3x + 5y = 0 E) -3x + 5y = 0
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@SolomonZelman can you please help me!!!(:
Okay, first you have to find the slope of the line that passes through (the given points) A and B. Can you do that ?
is it 5/-3 ?
YES \(\LARGE\color{blue}{ \rm \frac{(0)-(5)}{(-3)-(-6)}=\frac{0-5}{-3+6} =\frac{-5}{3} }\)
So, now we can say \(\LARGE\color{blue}{ \rm y=-\frac{5}{3}~x~+b }\) And when the line goes through the origin, the "b" (the y-intercept) is zero.
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soo it would be C?
Yes.
thank you so much!!
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