Question

Input in standard form the equation of the given line.

The line through (0, -3) and (3, 0)

Answer 1

(y+3)=m(x) m=(-3-0)/(0-3)

Answer 2

that doesn't help me :(

Answer 3

erm see if this helps http://www.montereyinstitute.org/courses/Algebra1/COURSE_TEXT_RESOURCE/U04_L1_T4_text_final.html

Answer 4

first find the slope using the slope formula :
(y2 - y1) / (x2 - x1)
(0,-3)..x1 = 0 and y1 = -3
(3,0)...x2 = 3 and y2 = 0
now we sub
(0 - (-3) / (3 - 0)
(0 + 3) / 3
3/3 = 1
so our slope is 1

now we use y = mx + b
slope(m) = 1
you can use either of your points...(3,0)..x = 3 and y = 0
now we sub
0 = 1(3) + b
0 = 3 + b
-3 = b

our equation is : y = x - 3
but we need it in standard form Ax + By = C

y = x - 3 -- subtract x from both sides
-x + y = -3 -- multiply by -1 to make x positive
x - y = 3 <== standard form

Answer 5

slope of the line = change in y/corresponding change in x
points (0, -3) (3,0)
0--3/3-0 = 3/3 = 1
using one of the points (3,0) and y = mx + b
0 = (1)(3) + b gives b = -3
y = x -3
standard form Ax + By = C
rewrite to this form x - y = 3

Answer 6

great minds think alike :)