2.Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5) 3.The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)
@ganeshie8
start by finding the slope of RS
R(-1, 6) and S(5, 5) slope = ?
can u find ? we're doing the first question btw..
is it y = 6x - 6.5.
good try, but no.
slope = m = \(\large \dfrac{y_2 - y_1}{x_2 -x_1}\)
R(-1, 6) and S(5, 5) x1 y1 x2 y2
plug the values in slope formula, wat do u get ?
uhhh
im lost
slope = m = \(\large \dfrac{5-6}{5--1} = \dfrac{-1}{6}\)
I see im writing it down and its getting confusing
just takes practice wid 2-3 problems to feel confident :)
lol could i just get the answer that would save time since my school ends in 1 hour
This is the last test
if you don't beleeve we could screen share
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