Question

solve for 4*2^5x=21

.48
.42
.08
.31

Answer 1

\[4\times2^{5x}=21\]

Is this correct?

Answer 2

\[2^{5x}=\frac{ 21 }{ 4}\]

\[5x \log2= \log (\frac{ 21 }{ 4})\]

Solve for x....

Answer 3

so it would be .42?

Answer 4

@MrNood

Answer 5

I don't really care about the answer and have not calculated it.#
Have you rearranged the above equation for x=???

If you are happy with that and the answer is what you get then fine.

If you have not done the calculation then ask if there is a point you are stuck on..

Answer 6

ok i think thats what it is

Answer 7

Hmmm - I suggest you try the calculation again