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simplify the equation 3x / 21(x+y)
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fill in the blank 21 = 3 times ______
7 i know but the only problem is the x and y
so that means \[\Large \frac{3x}{21(x+y)}\] \[\Large \frac{3*x}{3*7(x+y)}\]
what term do you see cancelling?
the 3 thats is so would it be 1/7(x+y)
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good \[\Large \frac{3x}{21(x+y)}\] \[\Large \frac{3*x}{3*7(x+y)}\] \[\Large \frac{\cancel{3}*x}{\cancel{3}*7(x+y)}\] \[\Large \frac{x}{7(x+y)}\]
thank you
You can stop there or you can optionally distribute to go from \[\Large \frac{x}{7(x+y)}\] to \[\Large \frac{x}{7x+7y}\]
yw
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