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simplify the equation 6x/ 9(x+y) 3x*2/3*3(x+y) is where im stuck
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What term do you see cancelling?
the 3s is that it
So the answer is \[\Large \frac{2x}{3(x+y)}\] after you erase those '3's that cancel out
this is because x*2 is the same as 2*x or 2x
so it would be 2x/3x+3y
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either \[\Large \frac{2x}{3(x+y)}\] or \[\Large \frac{2x}{3x+3y}\]
they're both equivalent since that 3 is just being distributed through
okay thank you
np
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