In ΔABC, ∡A is a right angle, and m∡B = 45°.What is the length of BC? If the answer is not an integer, leave it in simplest radical form. The diagram is not drawn to scale.

Question

anonymous · Answer

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ghdoru11 · Answer

$$BC^2=BA^2+AC^2 so BC^2=17^2+17^2 \because we have an issoscel \triangle$$

anonymous · Answer

so would that be $$17\sqrt{2}$$

dumbcow · Answer

yes 
using trig its

sin(45) = 17/BC

BC = 17/sin(45)    ........ sin 45 = 1/sqrt2

BC = 17 sqrt2

anonymous · Answer

thank you #ghdoru11

anonymous · Answer

can you help with anther question?

anonymous · Answer

What are the ratios for sin A and cos A? The diagram is not drawn to scale.

anonymous · Answer

attachment

dumbcow · Answer

SOH CAH TOA

sin = opp/hyp
cos = adj/hyp
tan = opp/adj

anonymous · Answer

so it would be 
sin = 20/29
cos = 21/29
tan = 20/21

dumbcow · Answer

not quite...those are correct for angle "B"

start from reference point of angle "A"

anonymous · Answer

sin = 21/29
cos = 20/29
tan =21/20

dumbcow · Answer

correct

anonymous · Answer

thanks :D