MEDAL AND FAN DESPERATE... I JUST NEED TO KNOW HOW TO DO THE FIRST PROBLEM
A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)
the only reason why we would do part A is if we wanted to eliminate one of the variables in the process.
which variable do you think would be the 'simplest' to remove based on your own personal mathing skills.
x...
lol, either you are choosing x, or thats just some internet thing
lets say x can be removed ..... since -3 and -9 are multiples of each other, they share something in common, they can be easily modified for elimination the y parts, 7 and 5 are mathically simple, but they require fractions and people are for some reason afraid of fractions.
-3x + 7y = -16 -9x + 5y = 16 we want to multiply the top by some number, k, such that we get a 9x to play with -3kx = 9x when k=?
k=-3x/9x?
almost: divide by -3x :) k = 9x/-3x = 3
@amistre64
3(-3x + 7y = -16) -9x + 5y = 16 -3(3)x + 7(3)y = -16(3) -9x + 5y = 16 9x + 21y = -48 -9x + 5y = 16 now we have a modified equivalent setup to play with. we are now able to elimiate the x parts to only deal with finding y
we add the two equations...correct?
yes
9x + 21y = -48 -9x + 5y = 16 16y= -32 16 y=-2
so, when y=-2, what does x equl?
and ... 21+5 = 26, not 16
26y = -32 y = -32/26 = -16/13
oddly enough, im getting 2 different answers :/
so does y equal-2?
-3x + 7y = -16 -9x + 5y = 16 got it ... i did (3) .. not (-3) -3(-3)x + 7(-3)y = -16(-3) -9x + 5y = 16
9x - 21y = 48 -9x + 5y = 16 -------------- 0x -16y = 64 y = -4
foiled by a negative once again lol
by setting y=-4, we get x=-4 as a solution ... and part B says to see if this works in the original setup as well.
Join our real-time social learning platform and learn together with your friends!