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Mathematics 17 Online
OpenStudy (yanasidlinskiy):

@paki @vishweshshrimali5

OpenStudy (yanasidlinskiy):

\(\huge\cal\color{lime}{plz...~help!}\)

OpenStudy (vishweshshrimali5):

HL ?

OpenStudy (vishweshshrimali5):

Ohh okay then the required legs would be AD and BD. As, AD = CD (the symbol for same length is given in figure) BD = BD.

OpenStudy (yanasidlinskiy):

Yay!!:) Paki:) you're back!!!!

OpenStudy (vishweshshrimali5):

@paki . I am handing it over to you now. Its getting late here and I am really really tired. Bye

OpenStudy (yanasidlinskiy):

you mean you're going to sleep??

OpenStudy (vishweshshrimali5):

Yeah @YanaSidlinskiy

OpenStudy (yanasidlinskiy):

\(\huge\cal\color{springgreen}{goodnight!!!!!!}\)

OpenStudy (vishweshshrimali5):

I will have a look at the question tomorrow morning.

OpenStudy (yanasidlinskiy):

\(\huge\cal\color{purple}{:(}\)

OpenStudy (paki):

AD and CD are the required legs that allow the use of HL.... reason for this is that the line BD is perpendicular to AC... so when it is perpendicular then it bears to opposite 90 degree angles... since you know that congruent angles have congruent opposite sides... as a result of which AD is congruent to DC... its the reason of the hypotenuse side...

OpenStudy (paki):

good night vishwe

OpenStudy (yanasidlinskiy):

Yay!!! Thanx paki for more explanation!!!!

OpenStudy (yanasidlinskiy):

One more to go?? Tired??

OpenStudy (yanasidlinskiy):

@paki ??

OpenStudy (paki):

no... carry on...

OpenStudy (yanasidlinskiy):

Ok..I thought you were away again..

OpenStudy (paki):

no i am here...

OpenStudy (yanasidlinskiy):

I'll open up a new one..

OpenStudy (paki):

yeah... tag me then....

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