Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

@ganeshie8 can you check my work

OpenStudy (anonymous):

The graph below shows four straight lines, W, X, Y, and Z: graph of line P going through ordered pairs negative 2, negative 5 and 0, 3. Graph of line Q going through ordered pairs negative 1, negative 2 and 1, 6. Graph of line R going through ordered pairs negative 1, negative 4 and 1, 4. Graph of line S going through ordered pairs 0, negative 3 and 2, 5 Which line is represented by the function f(x) = 3x + 5? Line W Line X Line Y Line Z

OpenStudy (anonymous):

i chose line W

ganeshie8 (ganeshie8):

I don't see any graph / descriptions for Line W ?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

line W is wrong

ganeshie8 (ganeshie8):

f(x) = 3x + 5

ganeshie8 (ganeshie8):

heard of the term `y intercept` before ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

good :) whats the y intercept of given function : f(x) = 3x + 5 ?

OpenStudy (anonymous):

Line X

ganeshie8 (ganeshie8):

Correct ! very good job !!

OpenStudy (anonymous):

I have 4 more

OpenStudy (anonymous):

The table below shows the distance d(t) in feet that an object travels in t seconds: t (second) d(t) (feet) 2 64 4 256 6 576 8 1024 What is the average rate of change of d(t) between 2 seconds and 6 seconds, and what does it represent? 128 m/s; it represents the average speed of the object between 2 seconds and 6 seconds 80 m/s; it represents the average speed of the object between 2 seconds and 6 seconds 128 m/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds 80 m/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds

OpenStudy (anonymous):

For this one i chose D

ganeshie8 (ganeshie8):

lets see

ganeshie8 (ganeshie8):

at t = 6, d = 576 at t = 2, d = 64 right ?

OpenStudy (anonymous):

yes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!