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OpenStudy (anonymous):
Given that f(x) = 4x − 3 and g(x) = quantity of 2x minus 1, divided by 3, solve for g(f(2)).
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OpenStudy (anonymous):
A. 1
B. 3
C. 9
D. 15
OpenStudy (anonymous):
Start off by finding f(2), what's f(2)?
OpenStudy (anonymous):
f(x) = 4x-3
f(2) = ?
OpenStudy (anonymous):
than would it be 14?
OpenStudy (anonymous):
wait..??
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OpenStudy (anonymous):
Idk what you're talking about but when I asked for f(2) all you have to do is plug 2 where the x is in your original function.
f(2) = 4(2) - 3
OpenStudy (anonymous):
So what does that =?
OpenStudy (anonymous):
ohh lol for some reason i was tryin to find x subtracting 3 and multiplying 7 by 2, but ok what u did now makes since it equals 5
OpenStudy (anonymous):
Yes, now lets do g(f(2)) so we have the function
\[g(x) = \frac{ 2x-1 }{ 3 }\]
OpenStudy (anonymous):
Now plug in f(2) in that function, meaning plug in 5 into that function and solve.
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OpenStudy (anonymous):
\[g(f(2)) = \frac{ 2(5)-1 }{ 3 }\]
OpenStudy (anonymous):
g(x)=(2x-1)/3
f(2)=4(2)-3
g(f(2))=(2(4(2)-3)-1)/3
OpenStudy (anonymous):
okkkkkie sooo would it equal 3?
OpenStudy (anonymous):
Yes, does that make sense now?
OpenStudy (anonymous):
yasss! :D :D thank you soo so much! much better understanding of it!
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OpenStudy (anonymous):
:)
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
:)
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