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When we are given the figure, let's call the points A,B,C,D and E corresponding: |dw:1402548853517:dw| And we know DE is parallel to BC. Then we can deduce that angle ABC is equal to the angle ADE. The same way, Angle ACB must be equal to angle AED. All because the angles on parallel lines, repeat. But also we know that the triangles ABC and ADE share the angle Â. So there I have three angles, and that is enough to say, by the SSS theorem, that ADE is similar to ABC.
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