nth terms again
Find an equation for the nth term of the arithmetic sequence. a19 = -92, a20 = 6
i didnt know if putting lil v symbols to indicate that there going down would be confuing or not... so its basically like ^ except the opposite c: so av19=-92,av20=6
like theyre acting as downward arrows XD
hehe you have 20th term and 19th term so d will be 6-(-92) which is 98
where D is common difference
\[a_{19}=-92, a _{20}=6\]
yes i got it now we have to find the first term
so im just adding 98 every time?
so we have 6 = a + 98(19)
yep
an = -1856 + 98(n - 1) an = -1856 - 98(n - 1) an = -1856 - 98(n + 1) an = -1856 + 98(n + 1) these are much more complicated than they need to be.... i would understand more if it just said +98 if you increasing -98 if your decreasing XD
haha the answer is A :)
you know how fits the formula
Find the sum of the geometric sequence. 1/3, 2/3, 4/3, 8/3, 16/3 i think i can do this one XD cuz its just adding itd be 31/3 right?
hahaha yes yes but there is formula for geometric sum too
a*(1-r^n/1-r)
but its adding c:
haha xD yes yes
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