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Mathematics 9 Online
OpenStudy (anonymous):

Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: What is the distance, CD, between the boats? 461.9 ft 530.9 ft 646.4 ft 325.5 ft

OpenStudy (anonymous):

OpenStudy (anonymous):

@melody16 (hehe hi again :P) this one i just need help. i dont understand much of it

OpenStudy (anonymous):

Have you learned about special right triangles?

OpenStudy (anonymous):

30 60 90 45 45 45 those?

OpenStudy (anonymous):

yes, so the big triangle is a 30 60 90 triangle. and you know the length of one of the sides. How do you think you can use that information to find the length of the other side?

OpenStudy (anonymous):

the larger angle is the 90 and the smaller unmarked angle is the 60?

OpenStudy (anonymous):

the top one is 60 because ever triangle is 180 degrees and we know two angles. That's how you know it's 60.

OpenStudy (anonymous):

every*

OpenStudy (anonymous):

so we know the big triangle. How do we solve the problem with that info?

OpenStudy (anonymous):

what do you know about a 30 60 90 triangle?

OpenStudy (anonymous):

its a right triangle? are the leg lengths the same? and the hypotenuse different?

OpenStudy (anonymous):

@melody16

OpenStudy (anonymous):

Ok, the hypotenuse is twice the shortest leg. the side opposite of the 60 is whatever the other length√3 so the bottom leg is 400√3 but that is the whole thing. We need a piece of that, so we need to do the same for the smaller 30 60 90 triangle. try and see if you can do that by youself

OpenStudy (anonymous):

would we take the 400 thats the side opposite of the 60 in the smaller triangle in this case? and divide it by the squareroot of 3?

OpenStudy (anonymous):

@amistre64 can you help with this by chance? he had to go and im stuck now

OpenStudy (amistre64):

i see they were dealing with special triangle proportions. my first thought was tangents

OpenStudy (amistre64):

tan(60) = 400/x tan(30) = 400/(x+y) solve for y

OpenStudy (anonymous):

tan(30) = 400/(x+y) divide each side 30? tan=13.33(x+y) ? i think i did it wrong

OpenStudy (amistre64):

tan(30) is a single value ... divide each side by tan(30)

OpenStudy (amistre64):

tan(60) = 400/x x = 400/tan(60) ----------------------- tan(30) = 400/(x+y) x+y = 400/tan(30) y = 400/tan(30) - x .... but x=400/tan(60) y = 400/tan(30) - 400/tan(60)

OpenStudy (anonymous):

so i would take the opposite and adjacent sides of 30 and 60 in the big or small triangle?

OpenStudy (amistre64):

which method are you more comfortable with, working the trig functions, or playing with special triangles?

OpenStudy (anonymous):

i think trig would be easier

OpenStudy (amistre64):

me too, which is why i just walked thru the trig. the next thing to do is simply use a calculator to work it.

OpenStudy (amistre64):

y = 400/tan(30) - 400/tan(60) that calculator knows how to work it form there :) unless you know the values for the trig functions.

OpenStudy (anonymous):

its giving me a really small decimal when i try dividing 400 by tan 30 it does it before i even put 30 in. should i grab my scientific calc?

OpenStudy (amistre64):

you should yes, or use the wolf. http://www.wolframalpha.com/input/?i=400%2Ftan%2830%29+-+400%2Ftan%2860%29

OpenStudy (anonymous):

Oh! ill make sure to save that as a favorite! and thank you for all the help i really am grateful.

OpenStudy (amistre64):

good luck :)

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