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Mathematics 6 Online
OpenStudy (anonymous):

x^2-2x+3=0

OpenStudy (anonymous):

Find two numbers when you multiply them by each other they will give you three and when you add them together they give you -2.

OpenStudy (anonymous):

Thank you Bob I have tried to do that but this quadratic problem is not factor-able, and I don't know what else to do. I am currently trying to "complete the square" but this is not going too well.

OpenStudy (anonymous):

How about you use the quadratic formula?

OpenStudy (the_fizicx99):

Completing the square is a more tedious process compared to using the Quadratic formula. I can help you with completing the square, however I recommend using the formula.

OpenStudy (mathmate):

Are you sure the equation has no typo?

OpenStudy (mathmate):

Completing the square: \[x^2-2x+3=0\] \[(x-1)^2-1+3=0\] \[(x-1)^2=-2\] Solving for x-1 \[(x-1)=\sqrt{-2}\] \[x=1\pm\sqrt{2}i \]

OpenStudy (anonymous):

@mathmate I think you did an error.

OpenStudy (anonymous):

Sorry its my bad your right.

OpenStudy (mathmate):

@Boblovesmath Thank you for pointing out. What is it that doesn't work?

OpenStudy (mathmate):

Whew! :)

OpenStudy (anonymous):

I confused it I did x^2 - 2x -1 +1 +3 = 0 I thought eh x^2 -2x +1 are the ones that factor without the -1. Good Job!

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