Question

(m+n) (m-n) Last one Pls..

Answer 1

m(m-n)+ n(m-n)
m^2-mn + nm-n^2
m^2-n^2

this is also a special case known as the difference of 2 squares

Answer 2

i think.. this is not the right answer.... but your solution is correct..but..
Can you Look what i do with this...?
(m+n) (m-n)
m^2-mn
+nm-n^2
=m^2-? -n^2

Answer 3

the +mn is added to the -mn so they cancel out
for example if you had numbers it would be same as +3-3= 0

Answer 4

ahhh... Thanks .. now i know :)

Answer 5

you can always combine like terms nm is the same as mn
2*3 is the same as 3*2