Question

The equation of line WX is y = −2x − 5. Write an equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)


y = 1 over 2x + 3 over 2

y = negative 1 over 2x + 3 over 2

y = 1 over 2x − 3 over 2

y = − 1 over 2x − 3 over 2

Answer 1

given
y=-2x-5
so slope m1=-2

Answer 2

if slope of a perpendicular line is m2

Answer 3

it has to be perpendicular so the slope would be \[\frac{ 1 }{ 2}\], but how do i make it so it passes through point (-1, -2)?

Answer 4

we can write
m1*m2=-1
-2*m2=-1
m2=1/2

Answer 5

let the ewuation of perpendicular line is
y=m2*x+c

Answer 6

need to find out
c=?

Answer 7

put
x=-1
y=-2

Answer 8

tell me
c=?

Answer 9

-2=-1/2+c
c=-4+1
c=-3

Answer 10

also put m2=1/2

Answer 11

so it would be y - (-2) = 1/2 (x + 1)?

Answer 12

yes thats right

Answer 13

no

Answer 14

slope intetcept form is
y=mx+c

Answer 15

y-y1=m(x-x1)

Answer 16

-2=(1/2)*(-1)+c

Answer 17

c=?

Answer 18

y+2=1/2x + 1/2
-2 -2

y=1/2x -3/2 ?

Answer 19

c= 3/2?

Answer 20

-3/2 *

Answer 21

ok. u r right

Answer 22

Thanks guys

Answer 23

now u hv to put the value of m nd c into
y=mx+c

Answer 24

put
m=1/2
c=-3/2

Answer 25

tell me ur result

Answer 26

u r most welcome