Mathematics
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OpenStudy (anonymous):
Quadratic equations
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OpenStudy (anonymous):
I didn't get it
OpenStudy (anonymous):
what did you do
OpenStudy (anonymous):
Let the common root be lambda
After i used the cross multiplication method and got lambda to be 1/2
OpenStudy (ikram002p):
let \(\lambda \) be the common
\(a\lambda^2 +2c\lambda+ b= a\lambda^2 +2b\lambda +c =0 \)
OpenStudy (anonymous):
Ok
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OpenStudy (vishweshshrimali5):
Did you do the cross multiplication correctly ?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
@ikram002p and it is given b is not equal to c
OpenStudy (vishweshshrimali5):
First of all cancel a(lambda)^2
OpenStudy (anonymous):
ax^2 +2cx + b= 0
ax^2 +2bx +c =0
have a common root then b is not equal to c
a+4b+4c = 0
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OpenStudy (vishweshshrimali5):
and yes lambda = 1/2 is right
OpenStudy (vishweshshrimali5):
Now, multiply 4 on both sides in this equation:
ax^2 + 2bx + c = 0 and then put x = lambda = 1/2
OpenStudy (ikram002p):
s0
\( 2\lambda (c-b) - (c-b) =0 \)
OpenStudy (ikram002p):
ohk u did that already :D
OpenStudy (ikram002p):
where the rest of the Qn lol
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OpenStudy (anonymous):
0.25a + b +c = 0
OpenStudy (vishweshshrimali5):
Multiply by 4 both sides.
OpenStudy (ikram002p):
what was the thing u wanted to prove ?
OpenStudy (anonymous):
Not to prove anything
OpenStudy (anonymous):
a +4b + 4c =0
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OpenStudy (ikram002p):
ohk ^^
OpenStudy (anonymous):
a + 4(b+c) = 0
OpenStudy (vishweshshrimali5):
@No.name You will get this expression after multiplying by 4 on both sides in the last equation you wrote.
OpenStudy (anonymous):
Wait
OpenStudy (anonymous):
0.25a +c + b = 0
4a +4(b+c) = 0
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OpenStudy (anonymous):
Yeah i am getting it @vishweshshrimali5
OpenStudy (ikram002p):
^
OpenStudy (vishweshshrimali5):
Good
OpenStudy (anonymous):
How would that lead us to the answer
OpenStudy (vishweshshrimali5):
Can you please repost your question ? I don't know the part after that.
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OpenStudy (anonymous):
Okay
OpenStudy (vishweshshrimali5):
I meant the part of the question ;)
OpenStudy (vishweshshrimali5):
But, you already proved this part.
OpenStudy (ikram002p):
ohk then what T_T
u showed that already :'(
OpenStudy (anonymous):
ax^2 +2cx + b= 0
ax^2 +2bx +c =0
have a common root then b is not equal to c
Find
a+4b+4c =
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OpenStudy (vishweshshrimali5):
But, you found out that its equal to zero, already.
OpenStudy (anonymous):
I didn't
OpenStudy (anonymous):
No.name Human Calculator
0.25a +c + b = 0
4a/4 +4(b+c) = 0
OpenStudy (vishweshshrimali5):
It is
OpenStudy (anonymous):
Oh yes
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OpenStudy (anonymous):
(:
OpenStudy (vishweshshrimali5):
There you have it :)
OpenStudy (anonymous):
Yeah lol we proved it
OpenStudy (anonymous):
sorruy
OpenStudy (vishweshshrimali5):
np