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Mathematics 16 Online
OpenStudy (anonymous):

Quadratic equations

OpenStudy (anonymous):

I didn't get it

OpenStudy (anonymous):

what did you do

OpenStudy (anonymous):

Let the common root be lambda After i used the cross multiplication method and got lambda to be 1/2

OpenStudy (ikram002p):

let \(\lambda \) be the common \(a\lambda^2 +2c\lambda+ b= a\lambda^2 +2b\lambda +c =0 \)

OpenStudy (anonymous):

Ok

OpenStudy (vishweshshrimali5):

Did you do the cross multiplication correctly ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

@ikram002p and it is given b is not equal to c

OpenStudy (vishweshshrimali5):

First of all cancel a(lambda)^2

OpenStudy (anonymous):

ax^2 +2cx + b= 0 ax^2 +2bx +c =0 have a common root then b is not equal to c a+4b+4c = 0

OpenStudy (vishweshshrimali5):

and yes lambda = 1/2 is right

OpenStudy (vishweshshrimali5):

Now, multiply 4 on both sides in this equation: ax^2 + 2bx + c = 0 and then put x = lambda = 1/2

OpenStudy (ikram002p):

s0 \( 2\lambda (c-b) - (c-b) =0 \)

OpenStudy (ikram002p):

ohk u did that already :D

OpenStudy (ikram002p):

where the rest of the Qn lol

OpenStudy (anonymous):

0.25a + b +c = 0

OpenStudy (vishweshshrimali5):

Multiply by 4 both sides.

OpenStudy (ikram002p):

what was the thing u wanted to prove ?

OpenStudy (anonymous):

Not to prove anything

OpenStudy (anonymous):

a +4b + 4c =0

OpenStudy (ikram002p):

ohk ^^

OpenStudy (anonymous):

a + 4(b+c) = 0

OpenStudy (vishweshshrimali5):

@No.name You will get this expression after multiplying by 4 on both sides in the last equation you wrote.

OpenStudy (anonymous):

Wait

OpenStudy (anonymous):

0.25a +c + b = 0 4a +4(b+c) = 0

OpenStudy (anonymous):

Yeah i am getting it @vishweshshrimali5

OpenStudy (ikram002p):

^

OpenStudy (vishweshshrimali5):

Good

OpenStudy (anonymous):

How would that lead us to the answer

OpenStudy (vishweshshrimali5):

Can you please repost your question ? I don't know the part after that.

OpenStudy (anonymous):

Okay

OpenStudy (vishweshshrimali5):

I meant the part of the question ;)

OpenStudy (vishweshshrimali5):

But, you already proved this part.

OpenStudy (ikram002p):

ohk then what T_T u showed that already :'(

OpenStudy (anonymous):

ax^2 +2cx + b= 0 ax^2 +2bx +c =0 have a common root then b is not equal to c Find a+4b+4c =

OpenStudy (vishweshshrimali5):

But, you found out that its equal to zero, already.

OpenStudy (anonymous):

I didn't

OpenStudy (anonymous):

No.name Human Calculator 0.25a +c + b = 0 4a/4 +4(b+c) = 0

OpenStudy (vishweshshrimali5):

It is

OpenStudy (anonymous):

Oh yes

OpenStudy (anonymous):

(:

OpenStudy (vishweshshrimali5):

There you have it :)

OpenStudy (anonymous):

Yeah lol we proved it

OpenStudy (anonymous):

sorruy

OpenStudy (vishweshshrimali5):

np

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